t = 0.0 s
Fig. 6.1 A + B → AB in a closed box A B AB reacted

Steeper = faster. The curve flattens as reactants are used up.

Readings

last 3 s
A–B collisions
— /s
with E ≥ Eₐ
…
successful = rate
— /s
product AB
0 / 40

§1  The big idea

Two conditions for a reaction.

The rate of reaction depends on the number of successful collisions per unit time. Anything that makes successful collisions happen more often makes the reaction faster.

  1. i.

    Particles must collide

    Reactant particles can only react if they actually meet. The more often they collide — the higher the collision frequency — the more chances they have.

  2. ii.

    With at least the activation energy

    A collision only succeeds if it has enough energy. Activation energy, Eₐ, is the minimum energy colliding particles need in order to react.

§2  Factor by factor

What changes, and why.

Each factor works through one or both conditions. Try it loads that change into the lab above.

Temperature

frequency + energy
  1. Particles gain kinetic energy and move faster
  2. More frequent collisions
  3. A greater proportion of collisions have E ≥ Eₐ
  4. More successful collisions per unit time

The energy effect is the big one — don’t stop at “they collide more often”.

Concentration

frequency
  1. More particles per unit volume
  2. Particles closer together
  3. More frequent collisions
  4. More successful collisions per unit time

Say “per unit volume”, not just “more particles”. The share of successful collisions doesn’t change.

Pressure

frequency
  1. Same gas particles in a smaller volume
  2. More particles per unit volume
  3. More frequent collisions
  4. More successful collisions per unit time

Only for reactions involving gases. It works exactly like higher concentration.

Catalyst

energy
  1. Provides an alternative pathway
  2. …with a lower activation energy
  3. A greater proportion of collisions succeed
  4. More successful collisions per unit time

A catalyst does not give particles more energy, and it is not used up.

Increase…Collision frequencyShare with E ≥ EₐRate
Temperature↑↑ big effect↑
Concentration↑no change↑
Pressure (gases)↑no change↑
Catalystno change↑ lower Eₐ↑

§3  Exam technique

Write it for full marks.

Examiners look for a complete chain: change → particles → collisions → successful collisions per unit time → rate.

Model answer · 3 marks

Explain, in terms of particles, why increasing the temperature increases the rate of reaction.

  1. M1Particles have more (kinetic) energy / move faster.
  2. M2Collisions are more frequent (more collisions per second).
  3. M3A greater proportion of collisions have energy greater than or equal to the activation energy — so more successful collisions per second.

§4  Quick check

Did it stick?

Five questions. Your score is saved on this device and fills in the topic on the syllabus map.

What is meant by activation energy?

Eₐ is a minimum — a threshold. Collisions with less energy than this just bounce apart.

Which change increases the rate without changing the share of collisions that succeed?

Concentration only changes how often particles collide. Temperature and catalysts both change the proportion with energy ≥ Eₐ.

How does a catalyst increase the rate of reaction?

Particle energies are unchanged — the energy hill is lower, so more collisions get over it. The catalyst is chemically unchanged at the end.

Increasing the pressure would speed up which reaction?

Pressure only matters when the reactants are gases: squeezing them puts more particles in each unit of volume.

On a graph of product against time, what shows the fastest rate?

Rate is how quickly product forms — the gradient. The final height depends on how much reactant there was.

Next: measuring the rate.

Gas syringes, mass loss and drawing tangents are the next lesson in this topic.

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